Using subset in for loop

[sanderd]

Hi,

I'm working on a data-set, in which I would like to run the same analysis (table + graph) on 15 different options. Now I know I could write this code 15 times, for each option. But I was wondering whether I could do this through a for loop in order to reduce repetitive coding.

When I try to make a subset of the main data set based upon QueueDesc matches the p I keep running into Error in aggregate.data.frame(lhs, mf[-1L], FUN = FUN, ...) : no rows to aggregate. However, when I run the same subset but then with df_detail <- subset(df, QueueDesc == "(NL) CS (88503)") I do not experience any issues.

Extract of the code used:

all_queues <- list("(NL) CS (88503)", "(NL) CS (88499)")

for (p in all_queues) {
  df_detail <- subset(df, QueueDesc == p)
  ...
}

Any help would be appreciated!

[nirgrahamuk]

Hi!

To help us help you, could you please prepare a reproducible example (reprex) illustrating your issue? Please have a look at this guide, to see how to create one:

FAQ: How to do a minimal reproducible example ( reprex ) for beginners

A minimal reproducible example consists of the following items: A minimal dataset, necessary to reproduce the issue The minimal runnable code necessary to reproduce the issue, which can be run on the given dataset, and including the necessary information on the used packages. Let's quickly go over each one of these with examples: Minimal Dataset (Sample Data) You need to provide a data frame that is small enough to be (reasonably) pasted on a post, but big enough to reproduce your issue. Let's say, as an example, that you are working with the iris data frame head(iris) #> Sepal.Length Sepal.Width Petal.Length Petal.Width Species #> 1 5.1 3.5 1.4 0.…

[sanderd]

Hi!

Thanks for your reaction. In the meantime, I solved my issue while making a reprex.

My solution:

df_obs <- data.frame(stringsAsFactors = FALSE,
                 Fruit = c("Apple", "Apple", "Pear", "Pear", "Banana", "Banana"),
                 Date = c("22/02/2022", "23/02/2022", "22/02/2022", "23/02/2022","22/02/2022", "23/02/2022"),
                 Sold = c(5,3,6,2,8,6)
)

all_fruits <- list("Apple", "Pear", "Banana")

for (i in all_fruits) {
  df_i <- subset(df_obs, Fruit == i)
  print(df_i)
}```