Dear members

how to write the command of this function in R

if 0<x<1/2 y=(8/3)*x if 1/2<=x<1 y=(4/3) else y=0

Dear members

how to write the command of this function in R

if 0<x<1/2 y=(8/3)*x if 1/2<=x<1 y=(4/3) else y=0

Consider the function `case_when()`

from {dplyr}. It behaves sort of like the SQL equivalent, if you are familiar with that. The same applies for `between()`

, also from {dplyr}.

```
library(dplyr)
y <- case_when(between(x, 0, 1/2) ~ 8*x/3,
between(x, 1/2, 1) ~ 4/3,
TRUE ~ 0)
```

1 Like

this command doesn't work. I remind you that I work with R-studio 3.6.1

Could you explain why are you saying that command doesn't work? does it produce an error message? It doesn't produce the output you are expecting? if so, what would be that output?

Also, there is no RStudio 3.6.1 version, I think you mean R 3.6.1, which is not the same, take a look to this FAQ to understand the difference.

2 Likes

R has `if`

operator and also `else`

, so you basically can do the same.

See this chapter in advanced R

https://adv-r.hadley.nz/control-flow.html

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