data: study$Questions
t = 78.112, df = 122, p-value < 2.2e-16
alternative hypothesis: true mean is not equal to 0
99 percent confidence interval:
47.36637 50.64989
sample estimates:
mean of x
49.00813
Thanks for your response, so knowing that is there a shorter way to calculate the confidence intervals using normal distribution similar to that of the t distribution?