Split a list into two columns

[PeterHui]

How do I split this into two columns?

I have a list here that contains

[[1]]
[1] "A" "O"

[[2]]
[1] "F" "O"

[[3]]
[1] "F" "O"

[[4]]
[1] "F" "OP"

Is it possible to do this?

I tried to do do split(., " ") but it didn't do anything

[FJCC]

Here is one method.

MyList <- list(c("A","O"),c("F","O"),c("F","O"),c("F","OP"))

library(purrr)

map_dfr(MyList, ~set_names(.x, nm = c("V1", "V2")))
#> # A tibble: 4 x 2
#>   V1    V2   
#>   <chr> <chr>
#> 1 A     O    
#> 2 F     O    
#> 3 F     O    
#> 4 F     OP

^{Created on 2022-05-04 by the reprex package (v2.0.1)}

[yifanliu]

@PeterHui

[[1]]
[1] "A" "O"

[[2]]
[1] "F" "O"

[[3]]
[1] "F" "O"

[[4]]
[1] "F" "OP"

I'd like to provide you with another solution, though it by default turns the list into a matrix:

mx1 <- do.call(rbind,list(c("A","O"),c("F","O"),c("F","O"),c("F","OP")))
mx1
     [,1] [,2]
[1,] "A"  "O" 
[2,] "F"  "O" 
[3,] "F"  "O" 
[4,] "F"  "OP"

mx1[,1]
[1] "A" "F" "F" "F"
mx1[,2]
[1] "O"  "O"  "O"  "OP"

[PeterHui]

I have no idea why this works but it seems to work, it knows where to split it somehow