That's a good solution. I've been using:
df[is.na(df)] <- 0
but it does not fit in a pipe chain very smoothly. I really like
mutate_if(is.numeric, funs(replace_na(., 0)))
thanks for sharing what you figured out!
That's a good solution. I've been using:
df[is.na(df)] <- 0
but it does not fit in a pipe chain very smoothly. I really like
mutate_if(is.numeric, funs(replace_na(., 0)))
thanks for sharing what you figured out!