I've been using the following code to replace NA's with zeros:
mutate_all(funs(replace(., is.na(.), 0)))
Is there some more elegant option out there?
Thanks for your help.
I've been using the following code to replace NA's with zeros:
mutate_all(funs(replace(., is.na(.), 0)))
Is there some more elegant option out there?
Thanks for your help.
tidyr::replace_na() may be helpful (if your number of variables is not too large + cumbersome to write out manually)!
Thanks for the suggestion to look again at replace_na
. After some more experimentation these worked well and are slightly simpler:
mutate_all(funs(replace_na(., 0)))
mutate_if(is.numeric, funs(replace_na(., 0)))
Oh right, I forgot you could use mutate_all + replace_na and not have to type them all out
That's a good solution. I've been using:
df[is.na(df)] <- 0
but it does not fit in a pipe chain very smoothly. I really like
mutate_if(is.numeric, funs(replace_na(., 0)))
thanks for sharing what you figured out!
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Thanks
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