Hello All,
I am in need of your help. It is probably something small I am missing, but I am trying to take percentages in a column and mutate those into a new column and then use ifelse to put the percentages into categories such as good or bad.
The column is titled PovertyLev and uses percentages to gauge a persons poverty level
example = 76%
I want to create a new column and categorize poverty rates.
Do I need to convert and do something before I can categorize everything correctly?
Here is the coding structure I am using:
DF <- MASTER.SERVICE.REPORT.(3)
%>%
mutate(Eligability2 = if_else(PovertyLev >200%, "Good", "Bad"))
However, when I use the coding structure shown above, I get this error in R
Error: unexpected input in:
"DF <- MASTER.SERVICE.REPORT.(3)
%>%
mutate(Eligability2 = if_else(PovertyLev > 200%, "Good", "Bad"))"
All the help is greatly appreciated.
Thank you,
Ctalley13:
PovertyLev >200%
That is a logical operation, greater than, being performed on a string, "200%". You want PovertyLev to be numeric, 200
.
Would I just use as.numeric to convert the povertyLev column to whole numbers?
If so, how would I structure everything?
Thank you for your help.
If you have a choice, code the data so that percentages are represented by decimals.
PovertyLev <- c(.52,46,32,12,76)
If you are stuck with
PovertyLev <- c("52%","46%","32%","12%","76%")
use
PovertyLev <- c("52%","46%","32%","12%","76%")
as.numeric(gsub("%","",PovertyLev))/100
#> [1] 0.52 0.46 0.32 0.12 0.76
Wait until preparing a presentation table to format as a percentage.
PovertyLev <- c("52%","46%","32%","12%","76%")
scales::label_percent()(as.numeric(gsub("%","",PovertyLev))/100)
#> [1] "52.0%" "46.0%" "32.0%" "12.0%" "76.0%"
For more questions, see the FAQ: How to do a minimal reproducible example reprex
for beginners .
system
Closed
May 13, 2021, 11:27pm
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