Essentially, I would like to do a  b
, which results in c
below.
In a notsosimplified scenario:

a
has millions of rows and columns 
b
has only one row, but matching number of columns and column names 
c
should be same dimensions asa
a = data.frame(a = c(1, 2, 3, 4),
b = c(2, 3, 4, 5),
c = c(3, 4, 5, 6))
b = data.frame(a = 1,
b = 2,
c = 3)
c = data.frame(a = c(0, 1, 2, 3),
b = c(0, 1, 2, 3),
c = c(0, 1, 2, 3))
I know that this isn't really a tidyverse
problem, but I would like to use tidyverse
functions as much as possible, if at all possible. I tried to convert them into matrices first, as well as trying something funky with rowwise()
with no luck.
Would some subtraction be apply
able (applicable?) for matching column names between the dataframes?
Any solutions out there?