I am trying to loop through elements of a list containing NULL object using a purrr-like function. Any help would be greatly appreciated. I would like to do it using the `map`

family to achieve this if possible

```
library(reprex)
library(purrr)
library(glue)
# hi, I am trying to find a way to replace the element of a list
#Data set-up
#my list
mylist=list(
a=1,
b=NULL,
c=NULL,
d=0,
e=NULL)
# the data to repalce
ax = c(1,2,3)
bx = c(1,4,5)
cx = c(1,6,7)
dx = c(1,8,9)
ex = c(10,2,9)
#the long way
if(is.null(mylist$a)){
mylist$a = ax
}
if(is.null(mylist$b)){
mylist$b = bx
}
if(is.null(mylist$c)){
mylist$c = cx
}
if(is.null(mylist$d)){
mylist$d = dx
}
if(is.null(mylist$e)){
mylist$e = ex
}
mylist #this what I want
#> $a
#> [1] 1
#>
#> $b
#> [1] 1 4 5
#>
#> $c
#> [1] 1 6 7
#>
#> $d
#> [1] 0
#>
#> $e
#> [1] 10 2 9
#want to create a function to change the element of a list
#and loop through all of the elements using a purrr-like function
null_funct <- function(mylist_var=mylist, var){
if(is.null(mylist_var[[var]])){
mylist_var[var]= glue("{var}x")
}
}
list_to_loop <- c("a","b", "c", "d","e")
map(list_to_loop, null_funct, mylist_var=mylist)
#> [[1]]
#> NULL
#>
#> [[2]]
#> NULL
#>
#> [[3]]
#> NULL
#>
#> [[4]]
#> NULL
#>
#> [[5]]
#> NULL
#It does not give me the expected results
```

Created on 2021-02-05 by the reprex package (v0.3.0)