Format Date in ifelse function

[Drdinhluong]

I have two columns (symtpom_onset; and test_positive.
So now I want to transfer the information of test_positive to symptom_onset column. With condition, if symptom_onset is missing value.

And here my code

mutate(symptom_onset = ifelse(is.na(symptom_onset),(test_positive), symptom_onset))

=> the problem is the result of symptom_onset column was show different format date.
How can I fit it?

[andresrcs]

Hi!

To help us help you, could you please prepare a reproducible example (reprex) illustrating your issue? Please have a look at this guide, to see how to create one:

FAQ: How to do a minimal reproducible example ( reprex ) for beginners

A minimal reproducible example consists of the following items: A minimal dataset, necessary to reproduce the issue The minimal runnable code necessary to reproduce the issue, which can be run on the given dataset, and including the necessary information on the used packages. Let's quickly go over each one of these with examples: Minimal Dataset (Sample Data) You need to provide a data frame that is small enough to be (reasonably) pasted on a post, but big enough to reproduce your issue. Let's say, as an example, that you are working with the iris data frame head(iris) #> Sepal.Length Sepal.Width Petal.Length Petal.Width Species #> 1 5.1 3.5 1.4 0.…

[Drdinhluong]

In here, I have A, B colums by date. my concept is if A missing value then B - 21. I wrote the function:
data2 <- data1 %>% mutate(A=ifelse(is.na(A)==TRUE, B-21, B))
However, the result showed not format date by A colums.
Pls help me to solove?

[DavoWW]

Hi @Drdinhluong,
Here is how to use ifelse in the situation you describe:

suppressPackageStartupMessages(library(tidyverse))
df <- data.frame(A = c(NA, "2021-04-09", NA, "2021-04-21", NA),
                 B = c("2021-05-03", NA, "2021-05-05", "2021-05-02", "2021-05-05"))
df
#>            A          B
#> 1       <NA> 2021-05-03
#> 2 2021-04-09       <NA>
#> 3       <NA> 2021-05-05
#> 4 2021-04-21 2021-05-02
#> 5       <NA> 2021-05-05

# Check that the ifelse logic is correct
ifelse(is.na(df$A), df$B, df$A)
#> [1] "2021-05-03" "2021-04-09" "2021-05-05" "2021-04-21" "2021-05-05"

# Make changes to dataframe
df %>% 
  mutate(A = ifelse(is.na(A), B, A) ) -> df
df
#>            A          B
#> 1 2021-05-03 2021-05-03
#> 2 2021-04-09       <NA>
#> 3 2021-05-05 2021-05-05
#> 4 2021-04-21 2021-05-02
#> 5 2021-05-05 2021-05-05

^{Created on 2021-06-18 by the reprex package (v2.0.0)}

As @andresrcs suggests, your Reproducible Example should include some relevant data in text form (not just a screenshot from your monitor) because otherwise in order to help you someone has to type that data in to demonstrate a solution.
HTH

[Drdinhluong]

Hi DavoWW

Thank for your support.
I make at step # Check that the ifelse logic is correct
so the result is not logic, BUT incuba.data1 is data.frame. I checked it
Pls, help me.

[nirgrahamuk]

maybe sometimes when A is na, B might also be NA , so replacing A with B still gives you NA's ?