Error: incorrect number of dimensions

[rsoto310790]

Hello,

I am getting the following error when trying to add a new variable from a vector matrix onto my data frame:

hs_directory <- hs_directory %>% mutate(lat = lat_long[,1], long = lat_long[,2])

There's an error coming up: Error in lat_long[, 1] : incorrect number of dimensions

To see if my coding was wrong, I copied/pasted from the course I took the data from, but the same error message appears. Any suggestion?

Thanks!

[andresrcs]

The error message suggests that lat_long doesn't have the same number of rows than hs_directory but we can't know fore sure since you are not providing sample data.

Could you ask this with a minimal REPRoducible EXample (reprex)? A reprex makes it much easier for others to understand your issue and figure out how to help.

If you've never heard of a reprex before, you might want to start by reading this FAQ:

FAQ: How to do a minimal reproducible example ( reprex ) for beginners

A minimal reproducible example consists of the following items: A minimal dataset, necessary to reproduce the issue The minimal runnable code necessary to reproduce the issue, which can be run on the given dataset, and including the necessary information on the used packages. Let's quickly go over each one of these with examples: Minimal Dataset (Sample Data) You need to provide a data frame that is small enough to be (reasonably) pasted on a post, but big enough to reproduce your issue. Let's say, as an example, that you are working with the iris data frame head(iris) #> Sepal.Length Sepal.Width Petal.Length Petal.Width Species #> 1 5.1 3.5 1.4 0.…

[rsoto310790]

Hi!

I am having troubles trying to put my code into a reprex format. When I run the df_paste function I can easily create a new data frame, but when I run the reprex function on my sample data together with the code that's currently giving me trouble, the following message comes up:

It seems reprex cannot find the new sample data! However this message doesn't come up when using the iris data table:

Any idea why? What am I doing wrong?

[andresrcs]

You have to create the sample dataframe in the reprex itself, and paste the output of reprex() here directly not with screenshots, see this example:

• If you run reprex() like this

reprex({
    # Create the sample dataset with the output of datapasta::df_paste()
    sample_data <- data.frame(
        Sepal.Length = c(5.1, 4.9, 4.7, 4.6, 5, 5.4),
        Sepal.Width = c(3.5, 3, 3.2, 3.1, 3.6, 3.9),
        Petal.Length = c(1.4, 1.4, 1.3, 1.5, 1.4, 1.7),
        Petal.Width = c(0.2, 0.2, 0.2, 0.2, 0.2, 0.4),
        Species = as.factor(c("setosa", "setosa", "setosa", "setosa", "setosa",
                              "setosa")))
    
    # Now you can use the dataset in your reprex
    summary(sample_data)
})

• You get this result ready to be posted in the forum.

# Create the sample dataset with the output of datapasta::df_paste()
sample_data <- data.frame(
    Sepal.Length = c(5.1, 4.9, 4.7, 4.6, 5, 5.4),
    Sepal.Width = c(3.5, 3, 3.2, 3.1, 3.6, 3.9),
    Petal.Length = c(1.4, 1.4, 1.3, 1.5, 1.4, 1.7),
    Petal.Width = c(0.2, 0.2, 0.2, 0.2, 0.2, 0.4),
    Species = as.factor(c("setosa", "setosa", "setosa", "setosa", "setosa",
                          "setosa")))

# Now you can use the dataset in your reprex
summary(sample_data)
#>   Sepal.Length    Sepal.Width     Petal.Length    Petal.Width    
#>  Min.   :4.600   Min.   :3.000   Min.   :1.300   Min.   :0.2000  
#>  1st Qu.:4.750   1st Qu.:3.125   1st Qu.:1.400   1st Qu.:0.2000  
#>  Median :4.950   Median :3.350   Median :1.400   Median :0.2000  
#>  Mean   :4.950   Mean   :3.383   Mean   :1.450   Mean   :0.2333  
#>  3rd Qu.:5.075   3rd Qu.:3.575   3rd Qu.:1.475   3rd Qu.:0.2000  
#>  Max.   :5.400   Max.   :3.900   Max.   :1.700   Max.   :0.4000  
#>    Species 
#>  setosa:6  
#>            
#>            
#>            
#>            
#> 

^{Created on 2019-06-23 by the reprex package (v0.3.0)}