eliminate persons who have entries in a time laps of 20 seconds

oussama · October 31, 2021, 2:41pm

hey guys, i have a problem in my script, im trying to eliminate same rows with time laps of 20 seconds between the 2 datas, i've used ::
dplyr::mutate(heure=lubridate::hms(heure),time_laps=diff(heure))%>%

lubridate::make_difftime(time_laps,units="second")%>%

filter(time_laps>20)

but it return time_laps error : object is not found

andresrcs · October 31, 2021, 3:47pm

Hi!

To help us help you, could you please prepare a reproducible example (reprex) illustrating your issue? Please have a look at this guide, to see how to create one:

FAQ: How to do a minimal reproducible example ( reprex ) for beginners General

A minimal reproducible example consists of the following items: A minimal dataset, necessary to reproduce the issue The minimal runnable code necessary to reproduce the issue, which can be run on the given dataset, and including the necessary information on the used packages. Let's quickly go over each one of these with examples: Minimal Dataset (Sample Data) You need to provide a data frame that is small enough to be (reasonably) pasted on a post, but big enough to reproduce your issue. Let's say, as an example, that you are working with the iris data frame head(iris) #> Sepal.Length Sepal.Width Petal.Length Petal.Width Species #> 1 5.1 3.5 1.4 0.2…