Hi everybody, I was able to pivot longer an object by using pivot_longer and then pivot_wider. I want to know if it is possible to do with only pivot_longer command? Thanks.

```
# Data set
df = tibble(key=1:2, x_1=paste('x', 1:2, sep=''), x_2=paste('x', 3:4, sep=''),
y_1=paste('y', 1:2, sep=''), y_2=paste('y',3:4, sep=''),
z_1=paste('z', 1:2, sep=''), z_2=paste('z',3:4, sep=''))
df
# Desired output
df_long=tibble(key=rep(1:2,2), x=paste('x',1:4, sep=''), y=paste('y',1:4, sep=''), z=paste('z',1:4, sep=''))
df_long
# Long solution
pivot_longer(df,cols=2:7, names_to=c('var','rep'), names_pattern=("(.)_(.)"), values_to = 'val') %>%
pivot_wider(names_from='var', values_from='val')
```

mara
June 3, 2020, 3:29pm
2
Ooff! This one's tricky because you've basically got a variable value encoded in the column names, and I haven't come up with a better solution… Thought having a reprex showing the output might help, though

```
library(tidyverse)
df <- tibble(
key = 1:2, x_1 = paste("x", 1:2, sep = ""), x_2 = paste("x", 3:4, sep = ""),
y_1 = paste("y", 1:2, sep = ""), y_2 = paste("y", 3:4, sep = ""),
z_1 = paste("z", 1:2, sep = ""), z_2 = paste("z", 3:4, sep = "")
)
df
#> # A tibble: 2 x 7
#> key x_1 x_2 y_1 y_2 z_1 z_2
#> <int> <chr> <chr> <chr> <chr> <chr> <chr>
#> 1 1 x1 x3 y1 y3 z1 z3
#> 2 2 x2 x4 y2 y4 z2 z4
# Desired output
df_long <- tibble(key = rep(1:2, 2), x = paste("x", 1:4, sep = ""), y = paste("y", 1:4, sep = ""), z = paste("z", 1:4, sep = ""))
df_long
#> # A tibble: 4 x 4
#> key x y z
#> <int> <chr> <chr> <chr>
#> 1 1 x1 y1 z1
#> 2 2 x2 y2 z2
#> 3 1 x3 y3 z3
#> 4 2 x4 y4 z4
# Long solution
pivot_longer(df, cols = -key, names_to = c("var", "rep"), names_pattern = ("(.)_(.)"), values_to = "val") %>%
pivot_wider(names_from = "var", values_from = "val")
#> # A tibble: 4 x 5
#> key rep x y z
#> <int> <chr> <chr> <chr> <chr>
#> 1 1 1 x1 y1 z1
#> 2 1 2 x3 y3 z3
#> 3 2 1 x2 y2 z2
#> 4 2 2 x4 y4 z4
```

^{Created on 2020-06-03 by the reprex package (v0.3.0.9001)}

@mara , thanks for your reply. This is my first post and I will remember using reprex the next time. Best.

It can be done by using the `.value`

special name as the first argument in `names_to`

.

```
library(tidyverse)
df <- tibble(key = 1:2,
x_1 = paste("x", 1:2, sep = ""),
x_2 = paste("x", 3:4, sep = ""),
y_1 = paste("y", 1:2, sep = ""),
y_2 = paste("y", 3:4, sep = ""),
z_1 = paste("z", 1:2, sep = ""),
z_2 = paste("z", 3:4, sep = ""))
pivot_longer(df, cols = -key, names_to = c(".value", "rep"), names_pattern = ("(.)_(.)"))
#> # A tibble: 4 x 5
#> key rep x y z
#> <int> <chr> <chr> <chr> <chr>
#> 1 1 1 x1 y1 z1
#> 2 1 2 x3 y3 z3
#> 3 2 1 x2 y2 z2
#> 4 2 2 x4 y4 z4
```

^{Created on 2020-06-04 by the reprex package (v0.3.0)}

3 Likes

@siddharthprabhu Wow, this is a great solution. Thanks, I learn something new today.

system
Closed
June 11, 2020, 1:01pm
6
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