(Second try to post because first resulted in and internal server error)
Here is a incomplete and brittle way of doing this. The basics are you have to convert your predicate into a quosue then parse, i.e. use the pieces of, that quosure to build an expession that can be evaluated.
The problem you have is that a predicate like a == 1
needs to somehow be converted into something like config[1][["a"] == 1 for each list in you list of lists.
This example is brittle because it assumes that that the predicate looks something like a == 1 and not something more complicated. Any production solution would need to verify that the args passed in were predicates and handle more complicated predicates.
There is not much documentation on how to do this and the tidyverse is in flux so this might not work in the future. I put together a tutorial on how to do things like this with the caveat that the tidyverse is in flux.
suppressPackageStartupMessages(library(tidyverse))
config = list(list(a = 1), list(a = 3, b = 1), list(b = 2))
list_config <- function(l, pred) {
# make quosue out of pedicate
q <- rlang::enquo(pred)
# parse quosue to pull out left-hand, right-hand,
# and operator
ql <- rlang::expr_text(q[[c(2, 2)]])
qr <- rlang::expr_text(q[[c(2, 3)]])
qop <- rlang::expr_text(q[[c(2, 1)]])
# make logic selection vector
s <- purrr::map_lgl(1:length(l), function(i) {
c <- l[[i]]
if (is.null(c[[ql]])) {
# false if element is missing
FALSE
} else {
# make text expession out of parts of predicate
exp <- glue::glue("c[['{ql}']] {qop} {qr}")
# parse and eval this expression
rlang::eval_tidy(rlang::parse_quosure(exp))
}
})
# select the elements that meet the predicate
l[s]
}
list_config(config, a > 0)
#> [[1]]
#> [[1]]$a
#> [1] 1
#>
#>
#> [[2]]
#> [[2]]$a
#> [1] 3
#>
#> [[2]]$b
#> [1] 1
list_config(config, a == 1)
#> [[1]]
#> [[1]]$a
#> [1] 1