Running analysis on time data - estimating average time

[andresrcs]

@d.s.kumari

For example the "05:00" time changes to "0.08333" in numeric. Or 12 changes to 0.2.

Ok, your data says "0:05" (five minutes) not "05:00" (five hours) as you mentioned, so the result is correct "0:05" (five minutes) is equal to 0.08333 hours

library(hms)
as.numeric(parse_hm("0:05")) / 3600
#> [1] 0.08333333

I was assuming that your data is in HH:MM format, could you specify what is the actual format of your data and what are the units of your desired output?

@d.s.kumari

I am not sure how to use dput() or attach my file here. Hopefully this helps?

If you want to learn how to post a proper reproducible example (and use dput) check this link

FAQ: How to do a minimal reproducible example ( reprex ) for beginners

A minimal reproducible example consists of the following items: A minimal dataset, necessary to reproduce the issue The minimal runnable code necessary to reproduce the issue, which can be run on the given dataset, and including the necessary information on the used packages. Let's quickly go over each one of these with examples: Minimal Dataset (Sample Data) You need to provide a data frame that is small enough to be (reasonably) pasted on a post, but big enough to reproduce your issue. Let's say, as an example, that you are working with the iris data frame head(iris) #> Sepal.Length Sepal.Width Petal.Length Petal.Width Species #> 1 5.1 3.5 1.4 0.…