How to filter column with percent data?

tidyverse
,
4

Tom,

maybe this helps (but if not provide a reprex for your question) :

library(dplyr) 
#> 
#> Attaching package: 'dplyr'
#> The following objects are masked from 'package:stats':
#> 
#>     filter, lag
#> The following objects are masked from 'package:base':
#> 
#>     intersect, setdiff, setequal, union

toms_data <- data.frame(
   "Cocoa\nPercent" = c(80,45) ,
   Rating = c(4.5, 2.1)
 )
 
toms_data
#>   Cocoa.Percent Rating
#> 1            80    4.5
#> 2            45    2.1
 
toms_data %>%
  filter(Cocoa.Percent >=75, Rating >= 3.9)
#>   Cocoa.Percent Rating
#> 1            80    4.5
Created on 2021-08-28 by the reprex package (v2.0.0)