How to extract time fields from POSIXct database field with dplyr/dbplyr?

That does look like an excellent suggestion, and I can get it to work as expected in Microsoft SQL Server Management Studio:

SELECT DATEPART(hour,  '2015-11-09 03:10:00')
3
SELECT DATEPART(minute,'2015-11-09 03:10:00')
10
SELECT DATEPART(second,'2015-11-09 03:10:00')
0

But I don't understand where hour, minute and second are defined?

Strings enclosed in double quotes also work, but not strings in single quotes:

SELECT DATEPART("hour",  '2015-11-09 03:10:00')
SELECT DATEPART("minute",'2015-11-09 03:10:00')
SELECT DATEPART("second",'2015-11-09 03:10:00')

Either works (no quotes or double quotes) in RStudio (assuming valid TSQL connection HF):

Note: I replaced back-ticks in the code chunks below with quotes so preformatted text blocks will work.

No Quotes

' ' '{sql, connection="HF"}
SELECT DATEPART(hour,  '2015-11-09 03:10:00')
' ' '

Double quotes

' ' '{sql, connection="HF"}
SELECT DATEPART("hour",  '2015-11-09 03:10:00')
' ' '

Single Quotes

Error: 'SELECT DATEPART('hour', '2015-11-09 03:10:00')'
nanodbc/nanodbc.cpp:1587: 42000: [Microsoft][ODBC SQL Server Driver][SQL Server]Invalid parameter 1 specified for datepart.
Failed to execute SQL chunk

dplyr/SQL attempts

I can't get this to work with dplyr with or without quotes since hours always gets the single quotes in SQL that do not work:

dplyr: take4  = DATEPART(hour, LAB_COMPLETED_DT_TM)
sql:  Error in UseMethod("escape") : no applicable method for 'escape' applied to an object of class "function"
dplyr:  take4  = DATEPART("hour", LAB_COMPLETED_DT_TM) 
sql:   DATEPART('hour', "LAB_COMPLETED_DT_TM") AS "take4"
dplyr: take4  = DATEPART('hour', LAB_COMPLETED_DT_TM)
DATEPART('hour', "LAB_COMPLETED_DT_TM") AS "take4"

Is there a way to get "hour" instead of 'hour' in the SQL DATEPART call from dplyr?